Places to visit near

Kendall

Kendall is a town in Miami-Dade district, Florida, United States of about 75,371 people. Within 50 km by road there are 248 places to visit: 143 parks, 19 wildlife, forests & gardens and 20 churches. The must-see places are Pinecrest Gardens, Montgomery Botanical Center and Tropical Park.

25.6793° N, 80.3173° WPop. 75,371

© OpenStreetMap contributors
Within 30 km228 places
Within 50 km248
Must-see113
Notable163
Best timeNovember to March

Start here

The 3 places worth the trip

Places near Kendall by type

All 276 places by distance →

One day from Kendall

5 stops, one loop, back by 12:38 pm

35 km on the road, in driving order so you don’t double back. Times assume an 8 am start and typical visit lengths.

  1. Leave Kendall
  2. Deering Estatepark · 45 min
  3. Chapman Field Parkpark · 45 min
  4. Pinecrest Gardensgarden · 45 min
  5. Lake Osceolalake · 45 min
  6. Tropical Parkpark · 45 min
  7. Back in Kendall
Today’s loopKendallStopStraight lines between stops — distances are road estimates
Imagery © Esri, Maxar, Earthstar Geographics · © OpenStreetMap contributors

Questions people ask

What are the best places to visit near Kendall?

Pinecrest Gardens (garden, about 4 km), Montgomery Botanical Center (park, about 5 km), Tropical Park (park, about 6 km), Matheson Hammock Park (park, about 7 km), Chapman Field Park (park, about 7 km), Lake Osceola (lake, about 7 km).

How many tourist places are there within 50 km of Kendall?

248 places on Spotwander: 143 parks, 19 wildlife, forests & gardens, 20 churches, 19 museums, 15 forts & heritage.

Which is the nearest park to Kendall?

Continental Park, about 1 km by road; Coral Pine Park (1 km) is next.

Which is the nearest sanctuary to Kendall?

Banyan Drive Park, about 4 km by road; John C. Gifford Arboretum (8 km) is next.

What is a good one-day trip from Kendall?

Start in Kendall, visit Deering Estate, then Chapman Field Park, then Pinecrest Gardens, then Lake Osceola, then Tropical Park, and drive back — about 35 km by road in all.